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Author SHA1 Message Date
Stein_van_vliet
41a5346110 Plots! 2024-03-22 21:12:14 +01:00
Stein_van_vliet
43370eead3 Fixed Torque implement 2024-03-22 21:12:04 +01:00
3 changed files with 59 additions and 15 deletions

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@ -58,7 +58,7 @@
De wielen hebben de volgende eigenschappen: De wielen hebben de volgende eigenschappen:
\begin{align*} \begin{align*}
r &= 0.15 & [m] \\ r &= 0.075 & [m] \\
\mu_s &= 0,9 & [-] \\ \mu_s &= 0,9 & [-] \\
C_r &= 0,1 & [-] C_r &= 0,1 & [-]
\end{align*} \end{align*}
@ -121,8 +121,9 @@
\\ \\
F_{aand} &= F_{rol} \\ F_{aand} &= F_{rol} \\
\\ \\
T_{as} &= F_{aand} \cdot r \\ T_{as} &= F_{aand} \cdot r \cdot \frac{1}{4} \\
&=F_{rol} \cdot r & [Nm] &=F_{rol} \cdot r \cdot \frac{1}{4} \\
&=27.590625 & [mNm]
\end{align*} \end{align*}
\subsubsection{Versnellen} \subsubsection{Versnellen}
@ -135,9 +136,9 @@
&= 1.05 + 1.4715 \\ &= 1.05 + 1.4715 \\
&= 2.5215 & [N] &= 2.5215 & [N]
\\ \\
T_{as} &= F_{aand} \cdot r \\ T_{as} &= F_{aand} \cdot r \cdot \frac{1}{4} \\
&=(F_{eff}+F_{rol}) \cdot r \\ &=(F_{eff}+F_{rol}) \cdot r \cdot \frac{1}{4} \\
&=0.378225 & [Nm] &=47.278125 & [mNm]
\end{align*} \end{align*}
\subsubsection{Vertragen} \subsubsection{Vertragen}
@ -150,9 +151,9 @@
&= 1.4715 - 0.75 \\ &= 1.4715 - 0.75 \\
&= 0.7215 & [N] &= 0.7215 & [N]
\\ \\
T_{as} &= F_{aand} \cdot r \\ T_{as} &= F_{aand} \cdot r \cdot \frac{1}{4} \\
&=(F_{eff}-F_{rol}) \cdot r \\ &=(F_{eff}-F_{rol}) \cdot r \cdot \frac{1}{4} \\
&=0.108225 & [Nm] &=13.528125 & [mNm]
\end{align*} \end{align*}
\subsection{Dalende ondergrond} \subsection{Dalende ondergrond}
@ -194,8 +195,8 @@
F_{aand} &= 1.3743 - 5.03\\ F_{aand} &= 1.3743 - 5.03\\
&= -3.6557 & [N] &= -3.6557 & [N]
\\ \\
T_{as} &= F_{aand} \cdot r \\ T_{as} &= F_{aand} \cdot r \cdot \frac{1}{4} \\
&=-0.548355 & [Nm] &=-68.544375 & [mNm]
\end{align*} \end{align*}
De motor moet in dit geval dus tegenkracht leveren om de kar op en constante snelheid te houden. De motor moet in dit geval dus tegenkracht leveren om de kar op en constante snelheid te houden.
@ -214,9 +215,9 @@
&= 5.03 + 1.3743\\ &= 5.03 + 1.3743\\
&= 6.4043 & [N] &= 6.4043 & [N]
\\ \\
T_{as} &= F_{aand} \cdot r \\ T_{as} &= F_{aand} \cdot r \cdot \frac{1}{4} \\
&=(F_{z2}+F_{rol}) \cdot r \\ &=(F_{z2}+F_{rol}) \cdot r \cdot \frac{1}{4} \\
&=0.960645 & [Nm] &=120.080625 & [mNm]
\end{align*} \end{align*}
\subsection{Slip} \subsection{Slip}

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@ -1 +0,0 @@
print("wack")

44
src/plot.py Normal file
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@ -0,0 +1,44 @@
import matplotlib.pyplot as plt
scale = 1000
x_lim = 5200
y_lim = 600
ratio = 5
T_1a = [27.590625] * x_lim
T_1b = [47.278125] * x_lim
T_1c = [13.528125] * x_lim
T_2 = [68.544375] * x_lim #Absolute waarde, is eig. negatief
T_3 = [120.080625] * x_lim
w = range(0,x_lim)
plt.plot(w,T_1a,label="T_1a")
plt.plot(w,T_1b,label="T_1b")
plt.plot(w,T_1c,label="T_1c")
plt.plot(w,T_2,label="T_2")
plt.plot(w,T_3,label="T_3")
RE25_57 = [[129,0],[0,5050]]
RE25_57r = [[129*ratio,0],[0,5050/ratio]]
RE25_57nom = [30] * x_lim
RE25_57nomr = [30*ratio] * x_lim
RE25_49 = [[232,0],[0,10000]]
RE25_49r = [[232*ratio,0],[0,10000/ratio]]
plt.plot(RE25_57[1],RE25_57[0],label="xx57")
plt.plot(RE25_57r[1],RE25_57r[0],label="xx57r")
plt.plot(w,RE25_57nom,label="xx57nom",linestyle='dashed')
plt.plot(w,RE25_57nomr,label="xx57nomr",linestyle='dashed')
plt.plot(RE25_49[1],RE25_49[0],label="xx49")
plt.plot(RE25_49r[1],RE25_49r[0],label="xx49r")
plt.xlim(0,x_lim)
plt.ylim(0,y_lim)
plt.xlabel('n[rpm]')
plt.ylabel('T_as[mNm]')
plt.legend()
plt.show()