Fixed Torque implement
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doc/main.tex
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doc/main.tex
@ -58,7 +58,7 @@
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De wielen hebben de volgende eigenschappen:
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\begin{align*}
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r &= 0.15 & [m] \\
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r &= 0.075 & [m] \\
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\mu_s &= 0,9 & [-] \\
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C_r &= 0,1 & [-]
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\end{align*}
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@ -121,8 +121,9 @@
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\\
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F_{aand} &= F_{rol} \\
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\\
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T_{as} &= F_{aand} \cdot r \\
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&=F_{rol} \cdot r & [Nm]
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T_{as} &= F_{aand} \cdot r \cdot \frac{1}{4} \\
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&=F_{rol} \cdot r \cdot \frac{1}{4} \\
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&=27.590625 & [mNm]
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\end{align*}
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\subsubsection{Versnellen}
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@ -135,9 +136,9 @@
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&= 1.05 + 1.4715 \\
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&= 2.5215 & [N]
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\\
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T_{as} &= F_{aand} \cdot r \\
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&=(F_{eff}+F_{rol}) \cdot r \\
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&=0.378225 & [Nm]
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T_{as} &= F_{aand} \cdot r \cdot \frac{1}{4} \\
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&=(F_{eff}+F_{rol}) \cdot r \cdot \frac{1}{4} \\
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&=47.278125 & [mNm]
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\end{align*}
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\subsubsection{Vertragen}
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@ -150,9 +151,9 @@
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&= 1.4715 - 0.75 \\
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&= 0.7215 & [N]
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\\
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T_{as} &= F_{aand} \cdot r \\
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&=(F_{eff}-F_{rol}) \cdot r \\
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&=0.108225 & [Nm]
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T_{as} &= F_{aand} \cdot r \cdot \frac{1}{4} \\
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&=(F_{eff}-F_{rol}) \cdot r \cdot \frac{1}{4} \\
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&=13.528125 & [mNm]
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\end{align*}
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\subsection{Dalende ondergrond}
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@ -194,8 +195,8 @@
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F_{aand} &= 1.3743 - 5.03\\
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&= -3.6557 & [N]
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\\
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T_{as} &= F_{aand} \cdot r \\
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&=-0.548355 & [Nm]
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T_{as} &= F_{aand} \cdot r \cdot \frac{1}{4} \\
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&=-68.544375 & [mNm]
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\end{align*}
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De motor moet in dit geval dus tegenkracht leveren om de kar op en constante snelheid te houden.
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@ -214,9 +215,9 @@
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&= 5.03 + 1.3743\\
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&= 6.4043 & [N]
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\\
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T_{as} &= F_{aand} \cdot r \\
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&=(F_{z2}+F_{rol}) \cdot r \\
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&=0.960645 & [Nm]
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T_{as} &= F_{aand} \cdot r \cdot \frac{1}{4} \\
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&=(F_{z2}+F_{rol}) \cdot r \cdot \frac{1}{4} \\
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&=120.080625 & [mNm]
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\end{align*}
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\subsection{Slip}
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