Added Torque to equations
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doc/main.tex
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doc/main.tex
@ -119,7 +119,10 @@
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&= 0.1 \cdot 14.715 \\
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&= 1.4715 & [N]\\
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\\
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F_{aand} &= F_{rol}
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F_{aand} &= F_{rol} \\
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\\
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T_{as} &= F_{aand} \cdot r \\
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&=F_{rol} \cdot r & [Nm]
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\end{align*}
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\subsubsection{Versnellen}
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@ -131,6 +134,10 @@
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F_{aand} &= F_{eff} + F_{rol} \\
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&= 1.05 + 1.4715 \\
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&= 2.5215 & [N]
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\\
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T_{as} &= F_{aand} \cdot r \\
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&=(F_{eff}+F_{rol}) \cdot r \\
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&=0.378225 & [Nm]
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\end{align*}
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\subsubsection{Vertragen}
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@ -142,6 +149,10 @@
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F_{aand} &= F_{rol} - F_{eff} \\
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&= 1.4715 - 0.75 \\
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&= 0.7215 & [N]
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\\
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T_{as} &= F_{aand} \cdot r \\
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&=(F_{eff}-F_{rol}) \cdot r \\
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&=0.108225 & [Nm]
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\end{align*}
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\subsection{Dalende ondergrond}
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@ -182,6 +193,9 @@
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&= F_{aand} + 5.03 - 1.3743 = 0\\
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F_{aand} &= 1.3743 - 5.03\\
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&= -3.6557 & [N]
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\\
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T_{as} &= F_{aand} \cdot r \\
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&=-0.548355 & [Nm]
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\end{align*}
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De motor moet in dit geval dus tegenkracht leveren om de kar op en constante snelheid te houden.
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@ -199,6 +213,10 @@
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F_{aand} &= F_{z2} + F_{rol}\\
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&= 5.03 + 1.3743\\
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&= 6.4043 & [N]
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\\
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T_{as} &= F_{aand} \cdot r \\
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&=(F_{z2}+F_{rol}) \cdot r \\
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&=0.960645 & [Nm]
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\end{align*}
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\subsection{Slip}
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