arne/EV6_Aandrijftechniek
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Fixed Torque implement

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Stein_van_vliet 2024-03-22 21:12:04 +01:00
parent 4fb9bf3d3c
commit 43370eead3
1 changed files with 15 additions and 14 deletions
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doc/main.tex
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@ -58,7 +58,7 @@
De wielen hebben de volgende eigenschappen: De wielen hebben de volgende eigenschappen:
\begin{align*} \begin{align*}
r &= 0.15 & [m] \\ r &= 0.075 & [m] \\
\mu_s &= 0,9 & [-] \\ \mu_s &= 0,9 & [-] \\
C_r &= 0,1 & [-] C_r &= 0,1 & [-]
\end{align*} \end{align*}
@ -121,8 +121,9 @@
\\ \\
F_{aand} &= F_{rol} \\ F_{aand} &= F_{rol} \\
\\ \\
T_{as} &= F_{aand} \cdot r \\ T_{as} &= F_{aand} \cdot r \cdot \frac{1}{4} \\
&=F_{rol} \cdot r & [Nm] &=F_{rol} \cdot r \cdot \frac{1}{4} \\
&=27.590625 & [mNm]
\end{align*} \end{align*}
\subsubsection{Versnellen} \subsubsection{Versnellen}
@ -135,9 +136,9 @@
&= 1.05 + 1.4715 \\ &= 1.05 + 1.4715 \\
&= 2.5215 & [N] &= 2.5215 & [N]
\\ \\
T_{as} &= F_{aand} \cdot r \\ T_{as} &= F_{aand} \cdot r \cdot \frac{1}{4} \\
&=(F_{eff}+F_{rol}) \cdot r \\ &=(F_{eff}+F_{rol}) \cdot r \cdot \frac{1}{4} \\
&=0.378225 & [Nm] &=47.278125 & [mNm]
\end{align*} \end{align*}
\subsubsection{Vertragen} \subsubsection{Vertragen}
@ -150,9 +151,9 @@
&= 1.4715 - 0.75 \\ &= 1.4715 - 0.75 \\
&= 0.7215 & [N] &= 0.7215 & [N]
\\ \\
T_{as} &= F_{aand} \cdot r \\ T_{as} &= F_{aand} \cdot r \cdot \frac{1}{4} \\
&=(F_{eff}-F_{rol}) \cdot r \\ &=(F_{eff}-F_{rol}) \cdot r \cdot \frac{1}{4} \\
&=0.108225 & [Nm] &=13.528125 & [mNm]
\end{align*} \end{align*}
\subsection{Dalende ondergrond} \subsection{Dalende ondergrond}
@ -194,8 +195,8 @@
F_{aand} &= 1.3743 - 5.03\\ F_{aand} &= 1.3743 - 5.03\\
&= -3.6557 & [N] &= -3.6557 & [N]
\\ \\
T_{as} &= F_{aand} \cdot r \\ T_{as} &= F_{aand} \cdot r \cdot \frac{1}{4} \\
&=-0.548355 & [Nm] &=-68.544375 & [mNm]
\end{align*} \end{align*}
De motor moet in dit geval dus tegenkracht leveren om de kar op en constante snelheid te houden. De motor moet in dit geval dus tegenkracht leveren om de kar op en constante snelheid te houden.
@ -214,9 +215,9 @@
&= 5.03 + 1.3743\\ &= 5.03 + 1.3743\\
&= 6.4043 & [N] &= 6.4043 & [N]
\\ \\
T_{as} &= F_{aand} \cdot r \\ T_{as} &= F_{aand} \cdot r \cdot \frac{1}{4} \\
&=(F_{z2}+F_{rol}) \cdot r \\ &=(F_{z2}+F_{rol}) \cdot r \cdot \frac{1}{4} \\
&=0.960645 & [Nm] &=120.080625 & [mNm]
\end{align*} \end{align*}
\subsection{Slip} \subsection{Slip}